technical data Top chain Selection
The latter half of this page also introduces the following selection examples:
(Click on each item to scroll to the main text.)
- *WT0700 series selection example
- *WT1500 series, WT1510 series, BTN5 type selection example
- *WT2525VG-K type selection example
Selection example of Plastic modular chain (mold-to-width)
WT0700 series selection example
Driven side nose bar
●Calculation formula (SI unit: kN)
・ return-way tension
[A section tension: F A]
FA = m1・L・μ1・fn × 9.80665 × 10-3
- Transport side tension
[Tension at part B: F B]
FB = FA + {(m1 + m2) L・μ1 + m2・LS・μ2} × 9.80665 × 10-3
・Chain tension
F = FB
*) If there is no accumulation of transported goods, L S = 0
●Calculation example (SI units)
| Usage conditions | |
|---|---|
| Chain type | WT0705-W300-LFG (m1=5.9×0.3=1.77kg/m) |
| Chain Width | 300mm |
| Layout | L=2m |
| Chain Speed | V=15m/min |
| Transported goods | 500ml aluminum can (real) |
| Amount of material transported (per 1m length) | m2 =139kg/m 2 (523g/piece) ×0.3m=41.7kg/m |
| wearstrip | Ultra-high molecular weight polyethylene (Plastic rail) |
| Accumulation Distance | Ls=2m |
| Lubrication | dry |
| Ambient temperature | 20℃ |
| Dynamic friction coefficient between chain and wearstrip | μ1=0.2 |
| Coefficient of dynamic friction between the chain and the conveyed object | μ2=0.2 |
| Nose bar coefficient | fn=1.8 |
・ return-way tension
[A section tension: F A]
FA = 1.77 × 2 × 0.2 × 1.8 × 9.80665 × 10-3 = 0.0125kN
- Transport side tension
[Tension at part B: F B]
FB = 0.0125 + {(1.77 + 41.7) × 2 × 0.2 + 41.7 × 2 × 0.2} × 9.80665 × 10-3 = 0.35kN
・Use judgment
Maximum allowable load ≧ F B'
Convert to per 1m of chain width
FB' = 1000 × FB 300 = 1.17(kN/m)
According to Allowable load graph, allowable tension is 2.5 (kN/m)
2.5(kN/m)≧1.17(kN/m)
Selection chains are available.
Front nose bar
●Calculation formula (SI unit: kN)
・ return-way tension
[A section tension: F A]
FA = 1.1m1・L・μ1 × 9.80665 × 10-3
- Transport side tension
[Tension at part B: F B]
FB= [FA + {(m1 + m2) L・μ1 + m2・LS・μ2} × 9.80665 × 10-3] × fn
・Chain tension
F = FB
*) If there is no accumulation of transported goods, L S = 0
●Calculation example (SI units)
| Usage conditions | |
|---|---|
| Chain type | WT0705-W300-LFG (m1=5.9×0.3=1.77kg/m) |
| Chain Width | 300mm |
| Layout | L=2m |
| Chain Speed | V=15m/min |
| Transported goods | 500ml aluminum can (real) |
| Amount of material transported (per 1m length) | m2 =139kg/m 2 (523g/piece) ×0.3m=41.7kg/m |
| wearstrip | Ultra-high molecular weight polyethylene (Plastic rail) |
| Accumulation Distance | Ls=2m |
| Lubrication | dry |
| Ambient temperature | 20℃ |
| Dynamic friction coefficient between chain and wearstrip | μ1=0.2 |
| Coefficient of dynamic friction between the chain and the conveyed object | μ2=0.2 |
| Nose bar coefficient | fn=1.8 |
・ return-way tension
[A section tension: F A]
FA = 1.1 × 1.77 × 2 × 0.2 × 9.80665 × 10-3 = 0.0077kN
- Transport side tension
[Tension at part B: F B]
FB = [0.0077 + {(1.77 + 41.7) × 2 × 0.2 + 41.7 × 2 × 0.2} × 9.80665 × 10-3] × 1.8 = 0.62kN
・Use judgment
Maximum allowable load ≧ F B'
Convert to per 1m of chain width
FB' = 1000 × FB 300 = 2.07(kN/m)
According to Allowable load graph, allowable tension is 2.5 (kN/m)
2.5(kN/m)≧2.07(kN/m)
Selection chains are available.
Nose bars on both ends
●Calculation formula (SI unit: kN)
・ return-way tension
[A section tension: F A]
FA = m1・L・μ1・fn × 9.80665 × 10-3
- Transport side tension
[Tension at part B: F B]
FB= [FA + {(m1 + m2) L・μ1 + m2・LS・μ2} × 9.80665 × 10-3] × fn
・Chain tension
F = FB
*) If there is no accumulation of transported goods, L S = 0
●Calculation example (SI units)
| Usage conditions | |
|---|---|
| Chain type | WT0705-W300-LFG (m1=5.9×0.3=1.77kg/m) |
| Chain Width | 300mm |
| Layout | L=2m |
| Chain Speed | V=15m/min |
| Transported goods | 500ml aluminum can (real) |
| Amount of material transported (per 1m length) | m2 =139kg/m 2 (523g/piece) ×0.3m=41.7kg/m |
| wearstrip | Ultra-high molecular weight polyethylene (Plastic rail) |
| Accumulation Distance | Ls=2m |
| Lubrication | dry |
| Ambient temperature | 20℃ |
| Dynamic friction coefficient between chain and wearstrip | μ1=0.2 |
| Coefficient of dynamic friction between the chain and the conveyed object | μ2=0.2 |
| Nose bar coefficient | fn=1.8 |
・ return-way tension
[A section tension: F A]
FA = 1.77 × 2 × 0.2 × 1.8 × 9.80665 × 10-3 = 0.0125kN
- Transport side tension
[Tension at part B: F B]
FB = [0.0125 + {(1.77 + 41.7) × 2 × 0.2 + 41.7 × 2 × 0.2} × 9.80665 × 10-3] × 1.8 = 0.63kN
・Use judgment
Maximum allowable load ≧ F B'
Convert to per 1m of chain width
FB' = 1000 × FB 300 = 2.1(kN/m)
According to Allowable load graph, allowable tension is 2.5 (kN/m)
2.5(kN/m)≧2.1(kN/m)
Selection chains are available.
f n (nose bar coefficient)
| Lubrication status | Nose bar coefficient fn |
|---|---|
| Sliding Type | |
| dry | 1.8 |
| soapy water | 1.35 |
WT1500 series, WT1510 series, BTN5 type selection example
Driven side nose bar
●Calculation formula (SI unit: kN)
・ return-way tension
[A section tension: F A]
FA = m1・L・μ1・fn × 9.80665 × 10-3
- Transport side tension
[Tension at part B: F B]
FB = FA + {(m1 + m2) L・μ1 + m2・LS・μ2} × 9.80665 × 10-3
・Chain tension
F = FB
*) If there is no accumulation of transported goods, L S = 0
●Calculation example (SI units)
| Usage conditions | |
|---|---|
| Chain type | WT1506-K30-ALF (m1=6.7×0.762=5.1kg/m) |
| Chain Width | 762mm |
| Layout | L=4m |
| Chain Speed | V=15m/min |
| Transported goods | 500ml aluminum can (real) |
| Amount of material transported (per 1m length) | m 2 =139kg/m 2 (523g/piece) ×0.762m=106kg/m |
| wearstrip | Ultra-high molecular weight polyethylene (Plastic rail) |
| Accumulation Distance | Ls=4m |
| Lubrication | dry |
| Ambient temperature | 20℃ |
| Dynamic friction coefficient between chain and wearstrip | μ1=0.15 |
| Coefficient of dynamic friction between the chain and the conveyed object | μ2=0.14 |
| Nose bar coefficient | fn=1.35 (bearing roller type) |
・ return-way tension
[A section tension: F A]
FA = 5.1 × 4 × 0.15 × 1.35 × 9.80665 × 10-3 = 0.04kN
- Transport side tension
[Tension at part B: F B]
FB = 0.04 + {(5.1 + 106) × 4 × 0.15 + 106 × 4 × 0.14} × 9.80665 × 10-3 = 1.28kN
・Use judgment
Maximum allowable load ≧ F B'
Convert to per 1m of chain width
FB' = 1000 × FB 762 = 1.68(kN/m)
According to Allowable load graph, allowable tension is 10.5 (kN/m)
10.5(kN/m)≧1.68(kN/m)
Selection chains are available.
Front nose bar
●Calculation formula (SI unit: kN)
・ return-way tension
[A section tension: F A]
FA = 1.1m1・L・μ1 × 9.80665 × 10-3
- Transport side tension
[Tension at part B: F B]
FB= [FA + {(m1 + m2) L・μ1 + m2・LS・μ2} × 9.80665 × 10-3] × fn
・Chain tension
F = FB
*) If there is no accumulation of transported goods, L S = 0
●Calculation example (SI units)
| Usage conditions | |
|---|---|
| Chain type | WT1506-K30-ALF (m1=6.7×0.762=5.1kg/m) |
| Chain Width | 762mm |
| Layout | L=4m |
| Chain Speed | V=15m/min |
| Transported goods | 500ml aluminum can (real) |
| Amount of material transported (per 1m length) | m 2 =139kg/m 2 (523g/piece) ×0.762m=106kg/m |
| wearstrip | Ultra-high molecular weight polyethylene (Plastic rail) |
| Accumulation Distance | Ls=4m |
| Lubrication | dry |
| Ambient temperature | 20℃ |
| Dynamic friction coefficient between chain and wearstrip | μ1=0.15 |
| Coefficient of dynamic friction between the chain and the conveyed object | μ2=0.14 |
| Nose bar coefficient | fn=1.35 (bearing roller type) |
・ return-way tension
[A section tension: F A]
FA = 1.1 × 5.1 × 4 × 0.15 × 9.80665 × 10-3 = 0.03kN
- Transport side tension
[Tension at part B: F B]
FB = [0.03 + {(5.1 + 106) × 4 × 0.15 + 106 × 4 × 0.14} × 9.80665 × 10-3] × 1.35 = 1.71kN
・Use judgment
Maximum allowable load ≧ F B'
Convert to per 1m of chain width
FB' = 1000 × FB 762 = 2.24(kN/m)
According to Allowable load graph, allowable tension is 10.5 (kN/m)
10.5(kN/m)≧2.24(kN/m)
Selection chains are available.
Nose bars on both ends
●Calculation formula (SI unit: kN)
・ return-way tension
[A section tension: F A]
FA = m1・L・μ1・fn × 9.80665 × 10-3
- Transport side tension
[Tension at part B: F B]
FB= [FA + {(m1 + m2) L・μ1 + m2・LS・μ2} × 9.80665 × 10-3] × fn
・Chain tension
F = FB
*) If there is no accumulation of transported goods, L S = 0
●Calculation example (SI units)
| Usage conditions | |
|---|---|
| Chain type | WT1506-K30-ALF (m1=6.7×0.762=5.1kg/m) |
| Chain Width | 762mm |
| Layout | L=4m |
| Chain Speed | V=15m/min |
| Transported goods | 500ml aluminum can (real) |
| Amount of material transported (per 1m length) | m 2 =139kg/m 2 (523g/piece) ×0.762m=106kg/m |
| wearstrip | Ultra-high molecular weight polyethylene (Plastic rail) |
| Accumulation Distance | Ls=4m |
| Lubrication | dry |
| Ambient temperature | 20℃ |
| Dynamic friction coefficient between chain and wearstrip | μ1=0.15 |
| Coefficient of dynamic friction between the chain and the conveyed object | μ2=0.14 |
| Nose bar coefficient | fn=1.35 (nose bar roller type) |
・ return-way tension
[A section tension: F A]
FA = 5.1 × 4 × 0.15 × 1.35 × 9.80665 × 10-3 = 0.04kN
- Transport side tension
[Tension at part B: F B]
FB = [0.04 + {(5.1 + 106) × 4 × 0.15 + 106 × 4 × 0.14} × 9.80665 × 10-3] × 1.35 = 1.72kN
・Use judgment
Maximum allowable load ≧ F B'
Convert to per 1m of chain width
FB' = 1000 × FB 762 = 2.26(kN/m)
According to Allowable load graph, allowable tension is 10.5 (kN/m)
10.5(kN/m)≧2.26(kN/m)
Selection chains are available.
f n (nose bar coefficient)
| Lubrication status | Nose bar coefficient fn | |
|---|---|---|
| Sliding Type | Bearing/roller type | |
| dry | 1.8 | 1.35 |
| soapy water | 1.35 | |
WT2525VG-K type selection example
Forward/reverse bottom drive selection example
●Calculation formula (SI unit: kN)
-return-way tension (follower side)
[A section tension: F A]
FA = 1.1m1・L1・μ1 × 9.80665 × 10-3
- Transport side tension
[Tension at part B: F B]
FB = 1.1{FA + (m1 + m2) × L・μ1 × 9.80665 × 10-3}
-return-way tension (drive side)
[C part tension: F C]
FC = FB + m1・L2・μ1 × 9.80665 × 10-3
・Chain tension
F = FC
●Calculation example (SI units)
| Usage conditions | |
|---|---|
| Chain type | WT2525VG-K36-G (m1=9.5×0.9144=8.7kg/m) |
| Chain Width | 914.4mm |
| Layout | L=10m, L1=6m, L2=4m |
| Chain Speed | V=10m/min |
| Transported goods | Cardboard sheet 900mm x 1800mm x 5mm 106.4 kg/m 2 = 861.8 g/sheet x 200 sheets (height 1 m) |
| Amount of material transported (per 1m length) | m2=106.4kg/m2×0.9144m =97.3kg/m |
| wearstrip | Ultra-high molecular weight polyethylene (Plastic rail) |
| Lubrication | dry |
| Ambient temperature | 20℃ |
| Dynamic friction coefficient between chain and wearstrip | μ1=0.25 |
-return-way tension (follower side)
[A section tension: F A]
FA = 1.1 × 8.7 × 6 × 0.25 × 9.80665 × 10-3 = 0.14kN
- Transport side tension
[Tension at part B: F B]
FB = 1.1 {0.14 + (8.7 + 97.3) × 10 × 0.25 × 9.80665 × 10-3} = 3.0kN
-return-way tension (drive side)
[C part tension: F C]
FC = 3.0 + 8.7 × 4 × 0.25 × 9.80665 × 10-3 = 3.09kN
・Use judgment
Maximum allowable load ≧ F B'
Convert to per 1m of chain width
FB' = 1000 × FB 914.4 = 3.34(kN/m)
According to Allowable load graph, allowable tension is 12.8 (kN/m)
12.8(kN/m)≧3.34(kN/m)
Selection chains are available.
